R: Convert a list of row-vectors of equal structure to a...

convertListOfRowsToDataFrame {BBmisc}

R Documentation

Convert a list of row-vectors of equal structure to a data.frame.

Elements are arranged in columns according to their name in each element of rows. Missing values are filled using NAs.

convertListOfRowsToDataFrame(rows,
  strings.as.factors = default.stringsAsFactors(), row.names, col.names)

`rows`	[`list`] List of rows. Each row is a list or vector of the same structure. That means all rows must have the same length and all corresponding elements must have the same class.
`strings.as.factors`	[`logical(1)`] Convert character columns to factors? Default is `default.stringsAsFactors()`.
`row.names`	[`character` \| `integer` \| `NULL`] Row names for result. By default the names of the list `rows` are taken.
`col.names`	[`character` \| `integer`] Column names for result. By default the names of an element of `rows` are taken.

[data.frame].

convertListOfRowsToDataFrame(list(list(x=1, y="a"), list(x=2, y="b")))

##   x y
## 1 1 a
## 2 2 b

[Package BBmisc version 1.7 Index]